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What values of b satisfy 4(3b + 2)^2 = 64?

User LKB
by
7.4k points

2 Answers

10 votes

Answer:

The value of 0 can satisfy b.

Explanation:

4(3b + 2)^2 = 64

(12b + 8)^2 = 64

(12b + 8)^2 = 64

144b + 64 = 64

144b + 64 - 64 = 64 - 64

144b = 0

144b / 144 = 0 / 144

b = 0

So, the value of 0 can satisfy b.

User Oscar LT
by
7.7k points
8 votes

Answer:

b =
(2)/(3) or b = -2

Explanation:

4(3b + 2)^2 = 64

Divide by 4 on both sides

(3b + 2)^2 = 16

Square root both sides

√(3b + 2)^2 = √16

3b + 2 = ±4

Subtract 2 on both sides

3b = ±4 - 2

Divide by 3 on both sides

b = (±4 - 2)/3

If 4 is positive, b is
(2)/(3)

If 4 is negative, b is -2

User Unclechu
by
8.7k points

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