a)
We would apply the transformer equation which is expressed as
Vp/Vs = Np/Ns
where
VP is the primary voltage
Vs is the secondary voltage
Np is the number of turns in primary
Ns is the number of turns in secondary
From the information given,
Vp = 11
Np = 100
Ns = 900
Thus,
11/Vs = 100/900
By cross multiplying, we have
100 * Vs = 900 * 11
100Vs = 9900
Vs = 9900/100
Vs = 99
the voltage output of the secondary is 99 V
b) We would apply another transformer equation which is expressed as
VpIp = VsIs
where
Ip is the input current in the primary coil
Is is the input current in the secondary coil
From the information given,
Ip = 3
Thus,
11 x 3 = 99 x Is
Is = 33/99
Is = 0.33
Current in the secondary coil is 0.33 A