Question

Standing in your tree house, 50 feet off the ground, you look

down at a 60° angle and notice a
Frisbee. Approximately how many feet from the base of the tree is the
Frisbee?

Answer 1

`\alpha = 60^o , \ b= 50 \ feet \\ \\ tan\alpha =(b)/(a)\\ \\tan60^o = (b)/(50)\\ \\√(3)=(b)/(50)\ \ / \cdot 50\\ \\b=50√(3) \approx 50\cdot 1.73 = 86.5 \ feet \\ \\Answer : \ Frisbee \ is \ about \ 50 \ feet \ from \ the\ base \ of \ the \ tree`