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How do you have factor y=6x²+24x-192 and find the zeros?
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How do you have factor y=6x²+24x-192 and find the zeros?

User Paul Bele
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y=6x^2+24x-192\\\\y=0\ \ \ \Leftrightarrow\ \ \ 6x^2+24x-192=0\ /:6\\\\x^2+4x-27=0\\\\x^2+2\cdot2\cdot x+2^2-2^2-27=0\\\\(x+2)^2-31=0\\\\(x+2)^2=31\ \ \ \Leftrightarrow\ \ \ (x+2= √(31) \ \ \ or\ \ \ x+2=- √(31))\\\\x=-2+ √(31)\ \ \ or\ \ \ x=-2- √(31)
User Wyattisimo
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