Question

The value of y varied jointly with x and z. If y=2 when z=110 and x=11, find the appropriate value of y when x=13 and z=195.

Answer 1

Given the ratio:

`\text{ x : y : z }\rightarrow\text{ 11 : 2 : 110}`

To be able to get the value of y at x = 13 and z = 195, let's recall how this ratio transforms into an equation:

At x : y : z

`(x)/(xyz)=(y)/(xyz)=(z)/(xyz)`

Let's now plugin the values to be able to find the value of y:

`(2)/((11)(2)(110))=(13)/((13)(y)(195))`

Let's simplify the equation:

`(2)/((11)(2)(110))=(13)/((13)(y)(195))\text{ }\rightarrow\text{ }(2)/(2420)=(13)/(2535y)`
`2(2,535y)=13(2,420)`
`5,070y\text{ = 31,460}`
`(5,070y)/(5070)\text{ = }\frac{\text{31,460}}{5070}`
`\text{ y = 6.2}05\text{ }\approx\text{ 6.21}`

Therefore, y = 6.21