Answer:
Explanations:
The capacitance, C = 4.50 μF
The charge, Q = 15.0 μC
The relationship between the capacitance (C), charge (Q), and the potential difference (V) is given as:
Q = CV
Substitute C = 4.5 and Q = 15 into Q = CV
15 = 4.5V
V = 15/4.5
V = 3.33 Volt
The potential difference required is