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The sum of four consecutive multiples of 5 is 230. What is the greatest of these numbers ?

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5n+5(n+1)+5(n+2)+5(n+3)=230\\\\5n+5n+5+5n+10+5n+15=230\\\\20n+30=230\\\\20n=200\ /:20\\\\n=10\ \ \ \Rightarrow\ \ \ 5(n+3)=5\cdot(10+3)=5\cdot13=65\\\\Ans.\ the\ greatest \ is\ 65.
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