Question

What is the distance between the points (4,3) and (1,-1) on the coordinateplane?

Answer 1

A. 5 units

Step-by-step explanation

The distance between two points (x₁, y₁) and (x₂, y₂) is given by the Pythagorean Theorem,

`d=\sqrt[]{(x_1-x_2)^2+(y_1-y_2)^2}`

In this case, the points are (4, 3) and (1, -1). The distance between them is,

`d=\sqrt[]{(4-1)^2+(3-(-1))^2}=\sqrt[]{3^2+(3+1)^2}=\sqrt[]{3^2+4^2}=\sqrt[]{9+16}=\sqrt[]{25}=5`

Hence, the distance between the given points is 5 units.