Question

There are two boxes containing only green and red pens.Box A has 7 red pens and 13 green pens.Box B has 6 red pens and 6 green pens.A pen is randomly chosen from each box.List these events from least likely to most likely.Event 1: choosing a red or green pen from Box A.Event 2: choosing a red pen from Box A.Event 3: choosing an orange pen from Box B.Event 4: choosing a green pen from Box B.Least likelyMost likelyEvent 3EventEvent 2Event 1

Answer 1

Pr(choosing an orange pen from Box B), Pr(chosing a red pen from box A) , Pr(choosing a green pen from Box B), Pr(chosing a red or green pen from box A)

Step-by-step explanation:

For Box A: 7 red pens and 13 green pens

Total pens = 13 + 7 = 20 pens

For Box B: 6 red pens and 6 green pens

Total pens = 6 + 6 = 12 pens

Event 1: choosing a red or green pen from Box A:

Probability of chosing a red or green pen from box A = Pr(red pen) + Pr(green pen)

Pr(red pen) = number of red pens/total pens = 7/20

Pr(red pen) = 0.35

Pr(green pen) = number of green pens/total pens = 13/20

Pr(green pen) = 0.65

Probability of chosing a red or green pen from box A = 0.35 + 0.65 = 1

Event 2: choosing a red pen from Box A

Pr(red pen) = number of red pens/total pens = 7/20 = 0.35

Event 3: choosing an orange pen from Box B

There are no orange pen Box

Pr(choosing an orange pen from Box B) = 0

Event 4: choosing a green pen from Box B

Pr(choosing a green pen from Box B) = 6/12 = 0.50

Arranging from least to most likely:

Pr(choosing an orange pen from Box B), Pr(red pen) = number of red pens/total pens , Pr(choosing a green pen from Box B), Pr(chosing a red or green pen from box A)