Which value of c makes y^2+8y+c a perfect square A. 4 B.16 C.64 D.8

asked Dec 7, 2015 39.4k views

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Which value of c makes y^2+8y+c a perfect square
A. 4 B.16 C.64 D.8

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$y^2+8y+c \\ \\ c=((b)/(2))^2=((8)/(2))^2=4^2 = 16 \\ \\y^2+8y+16 = (y+4)^2 \\ \\Answer : \ B. \ \ 16$

Jacob Lee answered Dec 11, 2015

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