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Subtract — 7x^2 + 4x + 2 from x^2 – 3.

User Pzo
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1 Answer

18 votes
18 votes

We are required to subtract -7x^2+4x+2 from x^2-3.

This is written as:


(x^2-3)-(-7x^2+4x+2)

First, we open the brackets


=x^2-3+7x^2-4x-2

Next, we collect like terms and simplify:


\begin{gathered} =x^2+7x^2-4x-3-2 \\ =8x^2-4x-5 \end{gathered}

Therefore:


(x^2-3)-(-7x^2+4x+2)=8x^2-4x-5

User Saverio Proto
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