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An oxygen tank contained 212 12/3 liters of oxygen before 27 1/3 liters were used. If the tank can hold 240 3/8 liters, how much space in the tank is unused

User Tahsmith
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1 Answer

3 votes
So, initially 240
(3)/(8) -212
(12)/(3) were empty:

this is :


240 (3)/(8) - 212 (12)/(3) = 240 (3)/(8) - 212 +4 = 240 (3)/(8) - 216= 24 (3)/(8)

12/4 is 4 so that's why i substituted it with 4.

now, later 27 1/3 were used so we add this tho the original empty space


24 (3)/(8)+ 27 (1)/(3) =
24 (9)/(24)+ 27 (8)/(24) =
51 (17)/(24)


which is the result!





User IlPADlI
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