Solve by using the perfect squares method.* x2 – 12x + 36 = 0

asked Sep 1, 2015 54.1k views

3 votes

by Lesya

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4 votes

x2 - 12x + 36 = 0
x2 - 2*x*6 +6^2 = 0
(x-6)^2 = 0
x-6 = 0
x = 6

Matteo Ragni answered Sep 3, 2015

8.3k points

3 votes

$x^2 -12x + 36 = 0\\ \\ (x-6)^2= 0 \\ \\ x-6=0 \\ \\ x=6$

Mishimay answered Sep 5, 2015

7.8k points

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