Question

'Solve using perfect square factoring patterns.
x^2 – 12x + 36 = 4'

Answer 1

`x^2-12x + 36 = 4 \\ \\x^2-12x + 36 - 4 =0\\ \\x^2-12x + 32 =0 \\ \\a=1 , \ b=-12, \ c =32\\ \\ \Delta =b^2-4ac = (-12)^2 -4\cdot1\cdot 32 = 144-128 =16\\ \\x_(1)=(-b-√(\Delta) )/(2a)=(12-√(16))/(2 )=( 12-4)/(2)=(8)/(2)= 4`


`x_(2)=(-b+√(\Delta) )/(2a)=(12+√(16))/(2 )=( 12+4)/(2)=(16)/(2)= 8`