Register
.75 through hole, counterbored to 1.63 diameter with a depth of 63
202k views
7 votes
.75 through hole, counterbored to 1.63 diameter with a depth of 63

User Tim Van Laer
by
3.8k points

1 Answer

0 votes

Answer:

51.5337423

Step-by-step explanation:

1.63 x .75 = 1.2225

63/1.2225 = 51.5337423

User Eugen Rieck
by
4.0k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

3.5m questions

4.5m answers

Other Questions

Implement this C program by defining a structure for each payment. The structure should have at least three members for the interest, principle and balance separately. And store all the payments in a structure
Solving for dominant strategies and the Nash equilibrium Suppose Andrew and Beth are playing a game in which both must simultaneously choose the action Left or Right. The payoff matrix that follows shows
Name the author the "the journey to the centre of the earth"​
The fully corrected endurance strength for a steel rotating shaft is 42 kpsi, the ultimate tensile strength is 120 kpsi, the yield strength Sy=65 kpsi, and the fatigue stress correction factor Kf = 1.96.
Regulation 433.3.3 gives six examples where th are permitted for safety reasons. Can you fill in the missing words? Exciter Drop zone for rotating machines. Supply circuits of lifting Dron zone
Link Copied!