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B is between A and C. AB=2x+1, BC=3x-4, and AC=62. Find the value of 'x', and determine if B is a bisector.

User Rnorris
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1 Answer

1 vote
∠AB = (2x + 1)°
∠BC = (3x - 4)°
∠AC = 62°

∠AB + ∠BC = ∠AC
(2x + 1)° + (3x - 4)° = 62°
(2x + 1) + (3x - 4) = 62
2x + 3x + 1 - 4 = 62
5x - 3 = 62
+ 3 + 3
5x = 65
5 5
x = 13°

Line B is a bisector between ∠AC.
User Roman Pfneudl
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