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what is the point slope form of an equation with the slope of 3/5 that passes through the point (10,-2)?

User Breiti
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Point slope form of a line:

y-y_1=m(x-x_1) where
m is your slope and
(x_1,\ y_1) is a point on your line.

For a line with a slope of 3/5 that passes through (10, -2)...

m=\frac35,\ x_1=10,\ y_1=-2
Let's plug these values into our formula.


y-(-2)=\frac35(x-10)

Subtracting by a negative is the same thing as adding (the double negatives cancel), so let's simplify that.


\boxed{y+2=\frac35(x-10)}

There's our equation in point-slope form. (keep in mind that you're not going to want to distribute that 3/5 or subtract the 2 or anything. You want to keep it similar to the formula.
User Saugat Mukherjee
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