Question

Find two consecutive integers whose product is 9 less than the square of the smaller number.

Answer 1

Set up an equation; let x represent the smaller number and x+1 is the larger number. x squared = x(x+1)+9. Solve to find the solution.
Hope that helped.

Answer 2

-9 and -8

Explanation:

We are given that

Product of two consecutive integers is 9 less than the square of the smaller number .

We have to find two consecutive integers

Let x and x+1 are two consecutive integers

According to question

`x(x+)=x^2-9`

Because x is smaller than x+1

`x^2+x=x^2-9`

`x^2+x-x^2=-9`

`x=-9`

Substitute the value of x then we get

`x+1=-9+1=-8`

Hence, the two consecutive integers are -9 and -8.