Question

A coolant lowers the temperature 15 C in a steel engine weighing 15250 N. What is the heat reduction (in kJ) in the steel engine?

Answer 1

Given that the temperature change of steel engine is

`\Delta T=15^(\circ)C`

Let the mass of steel engine be denoted by m.

The weight of the steel engine is

`\begin{gathered} W\text{ = 15250 N } \\ \text{mg = 15250 N} \\ m=(15250)/(9.8) \\ =1556.12kg \end{gathered}`

Also, the specific heat of coolant (water) is C = 4190 J kg/degC

We have to find the heat reduction.

The heat reduction can be calculated as

`\begin{gathered} Q\text{ =mC}\Delta T \\ =1556.12\text{ }*4190*15 \\ =97802.\text{14 kJ} \end{gathered}`