Question

What is the total power of three 10 ohm bulbs when they are connected in a 12 volt series circuit?

Answer 1

4.8 watts

Step-by-step explanation

the total power can be found by using the formula

`\begin{gathered} P=(V^2)/(R) \\ where\text{ P is the power} \\ V\text{ is the voltage} \\ R\text{ is the resistance} \end{gathered}`

so

Step 1

find the total resisitance:

if the bulbs are conected in serie ,then

`\begin{gathered} R_(eq)=R_1+R_2+R_3 \\ R_(eq)=10\text{ ohms+10 ohms+10ohmns} \\ R_(eq)=30\text{ ohms} \end{gathered}`

now, replace in the formula

`\begin{gathered} P=(V^(2))/(R) \\ P=\frac{(12\text{ V\rparen}^2}{30\text{ ohms }} \\ P=4.8\text{ watts} \end{gathered}`

therefore, the answer is

4.8 watts

I hope this helps you