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How do i solve

8x^(2/3)-39x^(1/3)-5=0

User Henrik R
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1 Answer

3 votes

8 x^{ (2)/(3) } -39 x^{ (1)/(3) } -5=0


8 \sqrt[3]{ x^(2) } -39 \sqrt[3]{ x^(1) } - 5=0


8 \sqrt[3]{ x^(2) } -39 \sqrt[3]{ x } = 5


8( \sqrt[3]{ x^(2) } )^(3) -39( \sqrt[3]{ x })^(3) =5 ^(3)


8 x^(2) -39x =5 ^(3)


8 x^(2) -39x =125


8 x^(2) -39x - 125 = 0

Hope this helps '-'

User Ritesh Waghela
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