Question

Please assist me in how to go about solving this problem

Answer 1

The given function is,

`f(x)=log_2x+1`

The graph of the function will be plotted below

A vertical asymptote is a vertical line that guides the graph of the function but is not part of it.

Hence, the vertical asymptote is at

`x=0`

The domain of a function f(x) is the set of all values for which the function is defined.

Hence, the domain of the function is

`\:\left(0,\:\infty \:\right)`

The range of a function is the complete set of all possible resulting values of the dependent variable.

Hence, the range of the function is

`\:\left(-\infty \:,\:\infty \:\right)`

Let get the f(x), when x = 2

`\begin{gathered} f(x)=log_2x+1 \\ \therefore f(2)=log_22+1 \\ Note:log_22=1 \\ \therefore f(2)=1+1=2 \\ \therefore f(2)=2 \end{gathered}`