How would you solve 3x^2-12=0?

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asked Nov 25, 2016 108k views

1 Answer

Simon Verbeke · Answer 1 · 2016-11-28T23:50:24+0000

3x^2 - 12 = 0

Personally, I would divide each side by 3 x^2 - 4 = 0

Then I would add 4 to each side x^2 = 4

Then I would take the square root of each side: x = +4
x = -4 .

Having found both solutions, I would relax with a cup of tea.

How would you solve 3x^2-12=0?

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