Question

Evaluate: i rly dont get this one. a/z+bw^2 for a=21, b=3,w=6and z=7.

a. 111
b. 108
c. 301
d. 1,771

Answer 1

So you have to Divide 21/7 which = 3 then you multiply 3*6^2 which is 108 then add 3 which equals A) 111.

Answer 2

The correct option is a) 111.

Explanation:

Consider the provided expression.

`(a)/(z)+bw^2`

Substitute the value of a=21, b=3, w=6 and z=7 in the above expression and solve.

`(21)/(7)+(3)(6)^2`

`3+(3)(36)`

`3+108`

`111`

Hence, the value of the expression for a=21, b=3,w=6 and z=7 is 111.

Thus, the correct option is a) 111.