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AC=3x+3,AB=-1+2x and BC=11 find x

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∠AC = (3x + 3)°
∠AB = (2x - 1)°
∠BC = 11°

∠AC + ∠AB + ∠BC = 360°
(3x + 3)° + (2x - 1)° + 11° = 360°
3x + 2x + 3 - 1 + 11 = 360
5x + 2 + 11 = 360
5x + 13 = 360
- 13 - 13
5x = 347
5 5
x = 69.4
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