Question

graph the line that passes through the points (3,-7) and (-3,1) and determine the equation of the line

Answer 1

Given: Two points (3,-7) and (-3,1).

Required: Graph the line that passes through the points (3,-7) and (-3,1) and determine the equation of the line.

Explanation:

Graph can easily be drawn, using the two given points (3,-7) and (-3,1).

Further, equation of line can be found using two point form. The line passing through two points (3,-7) and (-3,1) is

`\begin{gathered} y-1=(-7-1)/(3-(-3))(x-(-3)) \\ y-1=(-8)/(6)(x+3) \end{gathered}`

Solving further,

`\begin{gathered} y-1=-(4)/(3)(x+3) \\ 3(y-1)=-4(x+3) \end{gathered}`

So

`\begin{gathered} 3y-3=-4x-12 \\ 4x+3y+9=0 \end{gathered}`

Final Answer: The graph is drawn and equation of line passing through the points (3,-7) and (-3,1) is 4x+3y+9=0.