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Let U be a universal set with subsets A and B such that n(U)=118, n(A)=57, n(B′)=69, and n(A∩B)=11. Find the following:

n(B)=
n(A∪B)=
n((A∩B)′)=

1 Answer

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n(B)=n(U)-n(B')=118-69=49\\ n(A\cup B)=n(A)+n(B)-n(A\cap B)=57+49-11=95\\ n((A\cap B)')=n(U)-n(A\cap B)=118-11=107
User RetroGhost
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