Question

Which number is divisible by 3 and 5
a. 130
b. 325
c. 4113
d. 2040

Answer 1

The number divisible by both 3 and 5 is 2040.

Step-by-step explanation:

In order for a number to be divisible by both 3 and 5, it must be divisible by their product, which is 15. Looking at the given options, we can determine that the number divisible by both 3 and 5 is d. 2040. To confirm, let's check:

1. 130 ÷ 15 = 8 remainder 10
2. 325 ÷ 15 = 21 remainder 10
3. 4113 ÷ 15 = 274 remainder 3
4. 2040 ÷ 15 = 136

Only the number 2040 yields a whole number when divided by 15, so d. 2040 is the correct answer.

Answer 2

A number that is divisible by 5 is one that ends with either a 5 or 0.  To find a number that is divisible by 3 add up the digits and if they are divisible by 3, the number also is.  That rules c out because it doesn't end with a 5 or 0.  130 and 325 won't work because they are not divisible by 3.  The answer would be 2040.