The correct answer is:
6 ways.
Step-by-step explanation:
The two must be in the ten-thousands place. The number must be an even number; the only even digit left is 8, so this must be in the 1s place. Treating these as a "group," there is 1 way to arrange these two digits in that order.
This leaves us the remaining 3 digits to arrange in the middle. There are 3!=3(2)(1)=6 ways to arrange those 3 digits. This gives us a total of 6(1) = 6 ways to arrange these.