Question

Which accelerates from 0 to 25.0 m/s in 9.0 seconds

Answer 1

Acceleration of the cyclist is 2.1 m/s^2

The acceleration of the cyclist is not higher, that of the car is higher (2.8 m/s^2)

Explanation:

Given:

u1 = 0 m/s

v1 = 10.7 m/s

t1 = 5.1 sec

u2 = 0 m/s

v2 = 25 m/s

t2 = 9 sec

We can calculate the acceleration, using the following formula:

`a=(v-u)/(t)`

Replacing

`\begin{gathered} a_1=(v_1-u_1)/(t_1)=(10.7-0)/(5.1)=2.1m/s^2 \\ a_2=(v_2-u_2)/(t_2)=(25-0)/(9)=2.8m/s^2 \end{gathered}`

The acceleration of the cyclist is 2.1 m/s^2, it is not higher than the acceleration of the car, since it is equal to 2.8 m/s^2