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Suppose you want to solve the equation 2a b=2a where a and b are nonZero real numbers describe the solution to this equation justify you description

User UID
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To solve this equation we can first assume that both a and b are nonzero real numbers. Hence, A = 1 b = 1
1. 2 (1) + 1 = 2(1)

2.
2 + 1 = 2: now this a false equation since there is not equality, the equation cannot retain the equal sign but will become 2 + 1 > 2. Leaving the relationship unequal.

However, the alternative to this problem is to be b = 0. To oversee the rule in order to solve the equation retaining it as an “equation”. Further, there is no other solution for this equation. A = 1 b = 0
1. Which becomes 2(1) + 0 = 2(1)
2.
2 + 0 = 2 :
3. 2 = 2. Here we can observe the equality.




User Ela Dute
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2 votes

We have the following equation:


2a+b=2a

By solving this equation we have that:


2a+b=2a \\ \\ \therefore (2a-2a)+b=0 \\ \\ \therefore \boxed{b=0}

So, the only solution to this problem is
b=0 for any real value of
a


Then, the conclusion is:


a \ is \ a \ nonzero \ real \ number \\ \\ b \ \mathbf{must} \ be \ zero

User Vishu Rathore
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