Question

Find the slope, if it exists, I the line containing the pair of points. (-8,-2) and (-11,-6)

Answer 1

`(-8,-2), \ \ (-11,-6) \\ \\First \ find \ the \ slope \ of \ the \ line \ thru \ the \ points \: \\ \\ m= (y_(2)-y_(1))/(x_(2)-x_(1) ) \\ \\m=(-6-(-2))/(-11-(-8)) = (-6+2)/(-11+8) = (-4)/(-3) = (4)/(3)`

Answer 2

delta y = (-6 - -2) = ( -6 + 2) = -4
delta x = ( -11 - -8) = (-11 + 8) = -3
slope is (delta y)/(delta x) = (-4/-3) = 4/3