Let y=Mx+B be the equation of our line running the through points (-6,5/2) and (4,10). Our slope M = (y2-y1) ÷ (x2-x1) = (10-5/2) ÷ [4-(-6)] = (15/2) ÷ 10 = ¾. Picking (4,10) as our point solve for b:
y = Mx + B
10=¾*4 + B = 3 + B.
So B = 7. Therefore our equation of our line is given by y=¾x + 7.