Question

In the reaction, 3Cu + 2Al3+ → 3Cu2+ + 2Al, which substance is being reduced? Cu Al3+ Cu2+ Al

Answer 1

The reaction is
`3Cu+2Al^(3+)\rightarrow3Cu^(2+)+2Al`

The semi equations are hence the following :
`Cu-=Cu^(2+)+2e^-, Al^(3+)+3e^-=Al`

The substance being reduced is the one that gets the electrons.

Hence here it's Al