Question

A snowball is launched horizontally from the top of a building at v = 16.9 m/s. If it lands d = 44 meters from the bottom, how high (in m) was the building?

Answer 1

`v_x=16,9(m)/(s)\\ s=44m\\ g=10(m)/(s^2)\\\\ v_x=(s)/(t)\Rightarrow t=(s)/(v_x)\\\\ t=(44)/(16,9)\\\\ t=2,6s\\\\ h=(gt^2)/(2)\\\\ h=(10*2,6^2)/(2)\\\\ h=5*6,76\\\\ h=33,8m`