Question

Calculate the number of moles 3.15 g of HNO3 19.3 g of NaCl 21.25 g of NaNO3

Answer 1

The number of moles:
3.15g of
`HNO_(3)`
1 mole of
`HNO_(3)`- 63g.
x moles of
`HNO_(3)`- 3.15g

`x=(1\ mole*3.15g)/(63g)=(3.15)/(63)=0.05\ mole`

The number of moles:
19.3 g of NaCl
1 mole of NaCl- 58.44g.
x moles of NaCl- 19.3g.

`x=(1\ mole*19.3g)/(58.44g)=(19.3)/(58.44)=0.33\ mole`

The number of moles:
21.25 g of
`NaNO_(3)`
1 mole of
`NaNO_(3)`- 85g.
x moles of
`NaNO_(3)`- 21.25g.

`x=(1\ mole*21.25g)/(85g)=(21.25)/(85)=0.25\ mole`

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