Question

The smallest package weighed only 1/3 more than 1/2 the weight of the heaviest package. If the two packages combined weighed 100 kilograms, how much did the smaller package weigh?

Answer 1

Let the weight of the heaviet package = X
Weight of the smallest package = X/2+(1/3*X/2)
= X/2+X/6
= 2X/3
Then
X+2X/3 = 100
(3X+2X)/3 = 100
5X/3 = 100
X = 300/5
= 60
Then the weight of the smallest package = 2X/3
= 2*60/3
= 40
So the weight of the smallest package is 40 Kg.