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How do you find a segment endpoint if you are given one end point of(12,-8)and a midpoint of (3,18)

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\left\{{{(12 + x)/(2) = 3}\atop{(-8 + y)/(2) = 18}}\right. \\\left \{{{12 + x = 3}\atop{-8 + y = 18}}\right. \\\left\{{{x=-9}\atop{y=26}}\right.

End point of a Line Segment: (-9, 26)
User Kirill Ilichev
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