Final answer:
To solve the system of equations 15x-4y=-50 and 3x-2y=-16, we can use the method of substitution. The solution is x=-2 and y=5.
Step-by-step explanation:
To solve the given system of equations: 15x-4y=-50 and 3x-2y=-16, we can use the method of substitution.
Step 1: Solve one equation for one variable. We'll solve the second equation for x:
3x-2y=-16 ==> 3x=2y-16 ==> x=(2y-16)/3
Step 2: Substitute the value of x in the first equation:
15(2y-16)/3-4y=-50 ==> 10y-80-4y=-50 ==> 6y=30 ==> y=5
Step 3: Substitute the value of y back into any of the original equations to find x. Using the first equation:
15x-4(5)=-50 ==> 15x-20=-50 ==> 15x=-30 ==> x=-2
Therefore, the solution to the system of equations is x=-2 and y=5.