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Find the solution of the system of equations. 15x-4y=-50 3x-2y=-16

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Final answer:

To solve the system of equations 15x-4y=-50 and 3x-2y=-16, we can use the method of substitution. The solution is x=-2 and y=5.

Step-by-step explanation:

To solve the given system of equations: 15x-4y=-50 and 3x-2y=-16, we can use the method of substitution.

Step 1: Solve one equation for one variable. We'll solve the second equation for x:

3x-2y=-16 ==> 3x=2y-16 ==> x=(2y-16)/3

Step 2: Substitute the value of x in the first equation:

15(2y-16)/3-4y=-50 ==> 10y-80-4y=-50 ==> 6y=30 ==> y=5

Step 3: Substitute the value of y back into any of the original equations to find x. Using the first equation:

15x-4(5)=-50 ==> 15x-20=-50 ==> 15x=-30 ==> x=-2

Therefore, the solution to the system of equations is x=-2 and y=5.

User Croigsalvador
by
8.7k points
7 votes

Answer:

(2,5)

Step-by-step explanation:

15x-4y=-50

3x-2y=-16

15x-10y=-80

15x-4y=-50

-15x+10y=80

15x-4y=-50

10y=80

-4y=-50

6y=30

y=5

3x-2y=-16

3x-2(5)=-16

3x-10=-16

3x=6

x=2

Hope this helped <3

User Alistaircol
by
8.2k points

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