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What is x cubed minus 8

User DontPanic
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Since
x^3-8 is a sum of cubes, (-8 is -2 cubed) it can be factored like so:


a^3+b^3=(a+b)(a^2-ab+b^2)


a^3=x^3\implies a=x

b^3=-8\implies b=-2


x^3-8=(x+(-2))(x^2-x(-2)+(-2)^2)=\boxed{(x-2)(x^2+2x+4)}
User Nusi
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