Question

Choose ALL answers that describe the polygonCDEFifCD~DE~ EF ~ FC,mLC= 90° mLD = 90°, mLE = 90°and mLF= 90°. Parallelogram. Quadrilateral. Rectangle. Rhombus. Square. Trapezoid

Answer 1

From the question

We are given a polygon CDEF

Having the following properties

`\bar{CD}\cong\bar{DE}\cong\bar{EF}\cong\bar{FC}`

Also, We are given that

`\angle C=90^o,\angle D=90^o,\angle E=90^0,\angle F=90^o`

From these given properties we can have the given figure below

From the polygon drawn

We have that the polygon is a SQUARE

Also,

Since a square is a quadrilateral, then the polygon is a QUADRILATERAL

From the given properties

By definition of a rectangle, opposite sides are equal

Hence, a square is a rectangle

Therefore, the polygon can also be a rectangle

Finally, since a parallelogram has opposite sides to be equal, then the described polygon