Question

What are the exact solutions of x2 - 3x - 5 = 0? x = the quantity of negative 3 plus or minus the square root of 29 all over 2 x = the quantity of 3 plus or minus the square root of 29 all over 2 x = the quantity of 3 plus or minus the square root of 11 all over 2 x = the quantity of negative 3 plus or minus the square root of 11 all over 2

Answer 1

`x= (3+-√(29))/(2)`

Explanation:

x^2 - 3 x -5=0

To solve for x we apply quadratic formula

`x= (-b+-√(b^2-4ac))/(2a)`

From the given equation

a=1 , b=-3 and c=-5

Plug in all the values in the formula

`x= (3+-√((-3)^2-4(1)(-5)))/(2(1))`

`x= (3+-√(29))/(2)`

We cannot simplify square root (29)

So we keep as it is

`x= (3+-√(29))/(2)`