Factor completely: 3x2 – 24x + 36 A. (3x – 2)(x – 18) B. 3(x – 2)(x – 6) C. (x – 2)(x – 6) D. 2(x – 3)(x

asked Mar 26, 2016 165k views

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Factor completely: 3x2 – 24x + 36 A. (3x – 2)(x – 18) B. 3(x – 2)(x – 6) C. (x – 2)(x – 6) D. 2(x – 3)(x – 12)

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$3x^(2)-24x+36=3(x^(2)-8x+12)=3(x^(2)-2x-6x+12)= \\ \\ =3[x(x-2)-6(x-2)]=3(x-6)(x-2)$

\\\ Ben

Nico Nekoru answered Mar 26, 2016

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3 votes

$3x^2- 24x + 36=\\ 3(x^2-8x+12)=\\ 3(x^2-6x-2x+12)=\\ 3(x(x-6)-2(x-6))=\\ 3(x-2)(x-6)$

Hlt answered Apr 1, 2016

by Hlt

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