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Which equation could be used to solve this problem? The sum of two consecutive odd integers is 100. Find the integers. A.2n + 3 = 100 B.2n + 1 = 100 C.n + 4 = 100 D.2n + 2 = 100

User Yurymik
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odd integers - 2n+1
consecutive odd integers - 2n+1 + 2

equation 2x+1+2x+1+2=4n+4


4n+4=100\\ 4n=96\\ n=24\\\\ 2n+1=49\\ 2n+3=51\\ 49+51=100

the integers are 49 and 51


Maja
User Daniel Nesbitt
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an even integer is represented as 2n where n is an integer. an odd integer is represented as 2n+1
all even numbers are 2 away from the next even number

all odd numers are 2 away from the next odd number so

the sum of 2 consecutive odd intergesrs s 100

consecutive odd=(2n+1)+(2n+1+2) and so on

so consecutive odd =100 so
2n+1+2n+1+2=100

4n+4=100

the closest equation is


the equation is 4n+4
User DMarczak
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