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A 10-kg mass is suspended by a rope. What is the acceleration if the tension in the rope is 118 N while the mass is in motion?

User Govert
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2 Answers

4 votes

There are two forces on the mass:

-- the force of gravity downward ... (10kg) x (9.8 m/s²) = 98 newtons downward

-- the tension in the rope upward ... 118 newtons upward

The NET force on the mass is (118 - 98) = 20 newtons upward .

F = M a

Divide each side by 'M' : a = F / M

a = (20 newtons upward) / (10kg)

a = 2 m/s² upward

User Jezabel
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7.8k points
3 votes

There are two forces on the mass:

-- the force of gravity downward ... (10kg) x (9.8 m/s²) = 98 newtons downward

-- the tension in the rope upward ... 118 newtons upward

The NET force on the mass is (118 - 98) = 20 newtons upward .

F = M a

Divide each side by 'M' : a = F / M

a = (20 newtons upward) / (10kg)

a = 2 m/s² upward

User Josh Black
by
8.3k points