Question

Which value is a zero of the function defined by 6x^2+6x-36?

Answer 1

Only solve the equation:



`6x^2+6x-36=0\\ \\ \Delta=6^2-4.6.(-36)=36+864=900\\ \\ x=(-6 \pm √(900))/(2.6)=(-6 \pm30)/(12)\\ \\ x_1=(-36)/(12)=-3\\ \\ x_2=(24)/(12)=2`

Zeros of this function are: -3 and 2