Question

A box contains 4 chocobars and 4 ice-creams. Tom eats 3 of them one after another. What is the probability of sequentially choosing 2 chocobars and 1 ice-cream? Correct to 2 decimal places.

Answer 1

Given:

The number of choco bars = 4.

The number of ice creams = 4.

Aim:

We need to find the probability of sequentially choosing 2 choco bars and 1 ice cream.

Step-by-step explanation:

The total items in the box =4+4 =8.

`n(S)=8`

Let A be the event that chooses 2 choco bars.

There are 4 choco bars in the box.

`n(A)=4`

The probability of choosing 2 choco bars.

`P(A)=(n(A))/(n(S))`

Substitute known values,

`P(A)=(4)/(8)=(1)/(2)`

After taking 2 chocobars, the number of items in box = 8-2 =6.

`n(S_1)=6`

Let B be the event that takes one ice cream from the box.

There are 4 ice creams in the box.

`n(B)=4`

The probability of choosing one ice cream.

`P(B)=(n(B))/(n(S_1))`

Substitute known values.

`P(B)=(4)/(6)=(2)/(3)`

The probability of sequentially choosing 2 choco bars and 1 ice-cream

`=P(A)* P(B)`
`=(1)/(2)*(2)/(3)`
`=0.33`

Final answer:

The probability of sequentially choosing 2 choco bars and 1 ice cream is 0.33.