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What is the simplified form of (cube root of)16
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What is the simplified form of (cube root of)16

User Halaster
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1 Answer

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remember that
\sqrt[n]{x^m}= x^{ (n)/(m) } so

∛16=16^(1/3)
we know that
16=2^3 so
(2^3)^(1/3)
remember another rule
(x^m)^n=x^(mn) so
(2^3)^(1/3)=2^(3/3)=2^1=2
User Mesqueeb
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