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(12y2+17y-4)+9y2-13y+3)
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Mar 12, 2015
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(12y2+17y-4)+9y2-13y+3)
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Zia Qamar
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Prashant Pandey
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Clara found the product of 3 – 6y2 and y2 + 2. Her work is shown below. (3 – 6y2)(y2 + 2) = 3(y2) + (–6y2)(2) = 3y2 – 12y2 = –9y2 Is the student’s work correct?
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