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How do you solve the linear equations y=2x-3 and 4y=2x+8
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How do you solve the linear equations y=2x-3 and 4y=2x+8

User Rabeya
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1 Answer

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Subtract the first equation from the second to get:

4y-y=2x-2x+8+3

Simplifying, we see that 3y=11, so y=11/3. Substituting this into the first equation, we have:

11/3=2x-3

Adding 3, we see that 2x=20/3, so x=10/3.
User Nick Rossik
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